LSAT逻辑题分析：第三类人

Assume that all of the statements in the passage are true, If it is also true that no Montague is intemperate, then which one of the following must be true?

(A) The only people who can be crossed in live are intemperate Capulets.

(B) Anyone who is not a Copulet is a Montagues

(C) All intemperate people can be crossed in love.

(D) All intemperate people are Capulets

(E) All Capulets are intemperate.

这种题目我看到就晕，能否再讲讲.答案是e 。

原题的信息: 1. ALL Montague are not crossed in love 2. ALL Capulets are crossed in love3. Anyone who is not a Montague is intermerate 4. Montague 和Capulets集合不重叠

A提到了crossed in love的信息,而且是crossed in love 的必要条件..原文1,2信息根本无提到.错.
(B) 表示二选一..原文没提到.
(C) All intemperate people = NOT Montague    can be crossed in love.   原文没提到,可能还有第三类人.
(D) All intemperate people = NOT Montague    are Capulets  错
(E) All Capulets are intemperate. 由 3,4可得

可以看到BCD的错误其实是一样的...都是ASSUME除了Montague和 Capulets外没有第三类人.